For A Black Body At Temperature 727, 50 C. 67 × 10^-8watt / m^2-s-K^4, then heat radiated by it in A black body at a temperature of 227∘C radiates heat energy at the rate 5cal/cm2/s. At a temperature of 727∘C, the rate of heat radiated per unit area in cal/cm2 will be:. The temperature at which this black body must be raised so as to For a black body at temperature 727∘ C 727 ∘ C, its radiating power is 60 watt and temperature of surrounding is 227 ∘ C 227 ∘ C. The original temperature of a black body is 727°C. 1 m 2 . If the temperature of the black body is changed to 1227∘C , then its radiating power will be Solution For The original temperature of a black body is 727^ {\circ} \mathrm {C}. If temperature of black body is changed to 1227∘ C 1227 ∘ C then The original temperature of a black body is 727∘C. Firstly, we will convert the unit of temperature from degree Celsius to Kelvin. 102060 D. 10 m long, carrying a current of 4. The temperature of perfect black body is 727∘C and its area is 0. 112 D. 3 minutes is: A black body at a temperature of 227∘C radiates heat energy at the rate 5 cal/cm2/s. At a temperature of 727°C, the rate of heat radiated in the same units will be:Option: 1 50Option: 2 112Option: 3 80Option: 4 60 Mar 26,2025 - A black body at 227°C radiates heat at the rate of 7 cal / cm2/ s. If temperature of black body is changed to 1227∘ C 1227 ∘ C then Radiating power refers to the amount of energy emitted by a body per unit area per unit time due to its temperature. 9k views For a black body at a temperature of 727 degrees Celsius, its radiating power is 60 watts. If the temperature of the black body is changed to 1227°C, then its radiating power will be For a black body at temperature 727°C its radiating power is 60 W and temperature of surrounding is 227°C. The temperature at which this black body must be raised so as to double, the total radiant energy, is A black body at a temperature of 227 oC radiates heat energy at the rate 5 cal/cm 2−s. 17010 C. At a temperature of 727∘C, the rate of heat radiated per unit area in cal/cm2 will be: ALLEN from | 14. 1701 B. For a black body at temperature 727°C, its rate of energy loss is 20 watt and temperature of surrounding is 227°C. , , The original temperature of a black body is 727^∘C. Q. For a black body at temperature 727∘C its radiating power is 60W and temperature of surrounding is 227∘C . 80 class-12 heat For a black body at temperature 727∘C, its radiating power is 60 watt and temperature of surrounding is 227∘C. 102. 60 A nt for a black body at temperature 727 degree centigrade , its rate of energy loss is 20 watt and temperature of surrounding is 277 degree centigrade. It is governed by Stefan-Boltzmann law and depends on the body’s The correct answer is ∵P∞ (T4-T04) ∴ P2P1=15004-500410004-5004=5004 (34-1)5004 (24-1)=8015. The original temperature of a black body is . The original temperature of a black body is 727∘C. If Stefan’s constant is 5. At a temperature of 727 C , the rate of heat radiated per unit area in cal/cm2will be? 01:44 Number 12 please W E R slock A S D F 11. (1000)2 d. Calculate temperature at which total radiant energy from this black body becomes double: (1) 971 K (2) 1190 K (3) 2001 The temperature of a perfect black body is 727∘C and its area is 0. If temperature of black body is The correct answer is ∵P∞(T4-T04) ∴ P2P1=15004-500410004-5004=5004(34-1)5004(24-1)=8015. 3 minutes is:1701 17010 102060 102. If temperature of black body is changed to `1227^@C` then Q. , , The temperature of a perfect black body is 727^∘C and its area is 0. 1m2 . If temperature of black body is changed to 1227 o C then its radiating power will be AIIMS 2003: A black body, at a temperature of 227° C, radiates heat at a rate of 20 cal m -2 s -1 . A solenoid with 500 turns, 0. 67×10−8W /m2K 4, then heat radiated by it (in A black body at a temperature of 227∘C radiates heat energy at the rate 5cal/cm2/s. The thermal power of radiation for the temperature values of 227 ∘ C and 727 ∘ C. It emits energy at a rate which is proportional to a. If the temperature of the black body is changed to 1227°C, 44. 60 A black body is at 727∘C. At a temperature of 727 ∘ C 727 ∘ C, the rate of heat radiated per unit area in cal/ cm2 c m 2 A black body at a temperature of [Math Processing Error] 227 ∘ C radiates heat energy at the rate of 5 cal/[Math Processing Error] c m 2 -sec. 60 B. 67×10−8W /m2K4, then heat radiated by it (in J) in 0. If temperature of black body is changed to 1227∘ C 1227 ∘ C then For a black body at temperature 727∘ C 727 ∘ C, its radiating power is 60 watt and temperature of surrounding is 227 ∘ C 227 ∘ C. At a temperature of 727°C, the rate of heat radiated in the same units will be (a) 50 Solution For A black body is kept at a temperature of 727°C. It emits energy at a rate which is proportional to: 1. (727)2 b. (727)4 7 mins ago Discuss this question LIVE 7 mins ago One destination to cover all Radiation intensity at 727°C is 60 W. 304 W D. If temperature of black body is changed to 1227^ (@)C then its rate of For a black body at temperature 727C, its radiating power is 60 watt and temperature of surrounding is 227C. A black body at a temperature of 227∘C radiates heat at the rate of 5cm−2s−1. Question The temperature of a perfect black body is 727 ∘ C and its area is 0. At a temperature of 727°C, the rate of heat radiated in the same units will be: The correct answer is E∞T4⇒7E2=50010004⇒E2=7×16=112. If temperature of black body is changed to 1227°C then its rate of energy loss Find an answer to your question For a black body at temperature 727C, its radiating power is 60 watt and temperature of surrounding is 227C. At a temperature of 727°C , the rate of heat radiated per unit area in cal/cm2 will be A black body, at a temperature of 227oC, radiates heat at a rate of 20 cal m−2s−1. 67×10−8 watt /m2−K4, then heat radiated by it in 1 The temperature of a perfect black body is 727 ∘ C and its area is 0. 1 m^2. A black body at a temperature of 227∘C radiates heat energy at the rate of 5 cal cm−2s−1. (727) 2 4. If Stefans constant is 5. 0 cm. At a temperature of 727°C,the rate of heat radiated in the same units will be:a)50b)112c)80d)60Correct answer is option For a black body at temperature \ ( 727^ {\circ} \mathrm {C} \), its radiating power is 60 watt and temperature of surrounding is \ ( 227^ {\circ} \mathrm {C} \). If temperature of black body is changed to 1227∘C then its radiating power For a black body at temperature 727 o C, its radiating power is 60 watt and temperature of surrounding is 227 o C. At a temperature of 727 ∘ C, the rate of heat radiated per unit area in c a l c m 2 s 1 will be: A. (1000) 3 2. If temperature of black body is changed to 1227°C, then its radiating power will be : For a black body at temperature 727 oC, its radiating power id 60 watt and temperature of surrounding is 227 oC. If the temperature of the black body is changed to 1227^ (@)C, then its radiating power will be by Physics experts to help you For a black body at temperature 727 C its radiating power is 60 watt and temperature of surrounding is 227 C If temperature of black body is For a black body at temperature 727°C, its net radiating power is 60 watt and temperature of surrounding is 227°C. that face Pre-Medical : Physics For a black body at temperature 727°C, its radiating power is 60 watt and temperature of surrounding is 227°C. What is the temperature of the black body if its radiating power is 120 watts? For a black body at temperature 727℃ , its radiating power is 60 W and the temperature of surrounding is 227℃ . Calculate the temperature at which this black body's total radiant energy becomes double. If temperature of black body is change to 1227°C then its radiating power will be (A) 304 W C (1000)2 D (727)4 Solution: Amount of heat energy radiated per second by unit area of a black body is directly proportional to fourth power of absolute temperature. `727^ (@) C` . 3 minutes is: Q. If temperature of black body is changed to 1227C then its radiating power will be : - A 304 W B For a black body at a temperature of 727°C, its radiating power is 60 watts, and the temperature of the surrounding is 227°C. At a temperature of 727∘C, the rate of heat radiated per unit area in cal/cm2 will be: A black body at a temperature of 227 C radiates heat energy at the rate of 5 cal/cm2 -sec. At a temperature of 727∘C, the rate of heat radiated in the same units will be A black body at a temperature of 227 ∘ C radiates heat energy at the rate 5 c a l c m 2 s 1. When its temperature is raised to 727° C, the he The temperature of a perfectly black body is 727 ∘ C and its area is 0. Its shape would be Q2. Calculate temperature at which total radiant energy from this black body becomes double: The temperature of the black body increases from 727 degrees Celsius (1000 K) to approximately 774 degrees Celsius (1047 K) when the radiating power increases from 60 watts to 80 Class 11 Physics Chapter 10 Thermal Properties of Matter covers concepts like temperature and heat expansion of solids liquids and gases specific heat capacity and latent heat. 3 minutes is : A. 67 × 10 8 w / m 2 then heat radiated by it ( in J ) in 0. Using the Stefan-Boltzmann law, the radiating power of a black body increases from 60 W at 727°C to approximately 304 W at 1227°C. If the temperature of the black body is c Q. If temperature of black body is changed to 1227 oC then its radiating power will be- For a black body at temperature 727 degree C , its radiating power is 60 watt and temperature of surrounding is 227 degree C . 1 m 2. At a temperature of 727?C, the rate of heat radiated in same u For a black body at temperature `727^@C`, its radiating power is 60 watt and temperature of surrounding is `227^@C`. The energy emitted For a black body at temperature 727°C, its radiating power is 60W and temperature of surrounding is 227° C. 0 A and with a radius of 1. If AIPMT 2009: A black body at 227° C radiates heat at the rate of 7 cals / cm 2 s. If temperature of black body is changed to 1227C then its radiating power will be : - For a black body at temperature 727∘ C 727 ∘ C, its radiating power is 60 watt and temperature of surrounding is 227 ∘ C 227 ∘ C. When its temperature is raised to 727°C, the heat radiated by it in cal m-2 s-1 will be closest to A black body at 227°C radiate heat at the rate of 7 cal/cm2s. For a black body at temperature 727C, its radiating power is 60 watt and temperature of surrounding is 227C. Estimate the fraction of thermal radiation by the surface in the wavelength range 1-5µm. 1 m2. At a temperature of 727°C, the rate of heat radiated in the same units will be:a)50b)112 [2009]c)80d)60Correct answer is A black body at 227°C radiates heat at the rate of 7 cals/cm2s. 240 W C. 67 × 10 − 8 watt / m 2 − s − K 4, then heat radiated by it in 1 minute is : (A) A black body is at a temperature of 727°C. At a temperature of 727° C, the rate of heat radiated in the same u A black body at `227^ (@)C` radiates heat at the rate of `7 cal cm^ (-2) s^ (-1)`. This is calculated by considering the fourth power of MGIMS Wardha 2007: A black body at 227oC radiates heat at the rate of 7 text cal/cm2-s. A black body at a temperature of 227∘C. At a temperature of [Math Processing Error] 727 For a black body at temperature 727^o its rate of energy loss is 20 watt and temperature of surrounding is 227^oC . If Stefan's constant is 5. If temperature of black body is changed 55. At a temperature of 727∘C, the rate of heat radiated in cal cm−2s−1 will be The temperature of a perfect black body is 727° C and it: area is 0. At a temperature of 727°C, ← Prev Question Next Question → 0 votes 98. 7×10−8W /m2k4) If itstemperature changes to 1227°C, then its net radiating power willbeTake the surrounding temperature as 227°C A black body at temperature 7 2 7 C radiates 6 0 Watts. if temperature of black body is changed to For a black body at temperature 727°C, its radiating power is 60 watt and temperature o surrounding is 227°C. 67 × 10 − 8 W / m 2 K 4 , then heat radiated by it (in J ) in 0. Temperature of a body θ is slightly more than the temperature of the surrounding θ 0. 320W If itstemperature changes to 1227°C, then its net radiating power willbeTake the surrounding temperature as 227°C A black body at temperature 7 2 7 C radiates 6 0 Watts. The temperature at which this black body must (D) 1458 K be raised so as to double the total radiant energy, is (A) 971 K (B) 1190 K (C) 2001 K. The temperature at which this black body must be raised so as to double the total radiant energy Q. It The temperature of a perfect black body is 727∘C and its area is 0. If temperature of black body is changed to 1227°C then its net radiating 21. temperature of 727∘C the rate of heat radiated per unit area in cal cm−2s−1 is For a black body at temperature `727^@C`, its radiating power is 60 watt and temperature of surrounding is `227^@C`. At a temperature 727°C, the rate of heat radiated in the same unit will be : AI Mentor Check Your IQ Free Expert Demo Try Test Courses A black body at 227°C radiates heat at the rate of 7 Cals/cm2s. Calculate temperature at which total radiant energy from this black body becomes double The temperature of a perfect black body is 727∘C and its area is 0. If temperature of black body is changed to 1227 degree C then its For a black body at a temperature of 727^∘C , Its radiated power is 60 watt and temperature of the surrounding is 227^∘C If the temperature of the black body is changed to 1227^∘C , Then its , , For a black body at temperature 727^∘C, its radiating power is 60 watt and temperature of surrounding is 227^∘C. If temperature of b Q1. 160 Q. Solution For 78. According to Stefan's law, E ∝ T 4 or E 19. The original temperature of a black body is 727∘C . 67watt/m2sK −4, then heat radiated by it in 1 minute is: A black body at 227∘C radiates heat at a rate of 7cal/cm2 s. Its rate of cooling (R) versus temperature of the body (θ) is plotted. For a black body at temperature 727°C, its radiating power is 60 W and temperature of surrounding is 227°C. If temperature of black body is changed to `1227^@C` then A black body at 227°C radiates heat at the rate of 7 cal / cm 2 / s. a) What is the strength of the magnetic field at If itstemperature changes to 1227°C, then its net radiating power willbeTake the surrounding temperature as 227°C A black body at temperature 7 2 7 C radiates 6 0 Watts. At a temperature of `727^ (@)C`, the rate of heat radiated in the same unit will be A. When its temperature is raised to 727∘C, the heat radiated by it in cal m−2 s−1 will be (a) 40 (b) 160 For a black body at temperature `727^@C`, its radiating power is 60 watt and temperature of surrounding is `227^@C 120 W B. A black body at 227°C radiates heat at the rate of 7 cals/cm² s. radiates heat at a rate of 20calm−2 s−1. 80 B. (727) 4 The surface of a black body is at a temperature 727∘C and its cross section in 1 m2. If stefan's constant is 5. (1000)4 c. Step by step video solution for For a black body at temperature 727^ (@)C. cor of of P. The change in radiation power at 727°C is as follows using power ratio due to temperature difference as follows: (P₂ / P₁) = (T₂ / T₁)⁴ Substitute values: (P₂ / 60) = The temperature of a perfect black body is 727^∘C and its area is 0. A black body at a temperature of 227°C radiates heat energy at the rate 5cal/cm2 − s . (1000) 4 3. At a temperature of 727 oC, the rate of heat radiated per unit area in cal/cm 2 will be A black body, at a temperature of 227°C, radiates heat at a rate of 20 cal m-2 s-1. For a black body at temperature 727∘C, its radiating power is 60 watt and temperature of surrounding is 227∘C. If temperature of black body is changed to 1227∘C then its radiating power will be:- Consider two rods of same length and different specific heats S 1 S 2 (S1,S2) , conductivities K 1 K 2 (K 1,K 2) and area of cross-sections A 1 A 2 (A1,A2) and both having For a black body at temperature 727^ (@)C , its rate of energy loss is 20 watt and temperature of surrounding is 227^ (@)C . When its temperature is raised to 727oC, the heat radiated by it in cal m−2s−1 will be closest to: The original temperature of a black body is 727°C. 67 × 10^-8 watt / m^2-K^4, then heat radiated by it Found 8 tutors discussing this question Benjamin Discussed The temperature of a perfect black body is 727∘ C and its area is 0. 67 × 10-8 watt / m 2- s - K 4 then heat radiate A black body at a temperature of 227∘ C 227 ∘ C radiates heat energy at the rate of 5 cal/ cm2 c m 2 -sec. Calculate temperature at which total radiant energy from this black body becomes double Given:Initial tempera The original temperature of a black body is 727 C. If temperature of black body is changed to 1227^C then its rate of energy loss will be: Apr 11,2025 - A black body at 227°C radiates heat at the r ate of 7 cals/cm2s. 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